{"id":2164,"date":"2026-05-25T14:44:04","date_gmt":"2026-05-25T09:14:04","guid":{"rendered":"https:\/\/mymockmate.com\/notes\/?p=2164"},"modified":"2026-05-25T14:44:07","modified_gmt":"2026-05-25T09:14:07","slug":"ncert-class-9-maths-end-of-chapter-exercises-solutions-linear-polynomials","status":"publish","type":"post","link":"https:\/\/mymockmate.com\/notes\/ncert-class-9-maths-end-of-chapter-exercises-solutions-linear-polynomials\/","title":{"rendered":"NCERT Class 9 Maths End-of-Chapter Exercises Solutions \u2013 Linear Polynomials"},"content":{"rendered":"
\"image_pdf\"Save as PDF<\/span><\/a>\"image_print\"Print<\/span><\/a> <\/span><\/div>\n
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Short Intro<\/h1>\n\n\n\n

The End-of-Chapter Exercises of Chapter 2 \u201cIntroduction to Linear Polynomials\u201d help students revise important concepts like linear polynomials, polynomial evaluation, linear equations, graph plotting, linear growth, linear decay, and linear relationships. These detailed solutions are written in simple step-by-step format for better understanding and exam preparation.<\/p>\n\n\n\n

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Quick Information Box<\/h1>\n\n\n\n
Topic<\/th>Details<\/th><\/tr><\/thead>
Chapter<\/td>Introduction to Linear Polynomials<\/td><\/tr>
Exercise<\/td>End-of-Chapter Exercises<\/td><\/tr>
Subject<\/td>Mathematics<\/td><\/tr>
Class<\/td>Grade 9<\/td><\/tr>
Main Concepts<\/td>Polynomials & Linear Relationships<\/td><\/tr>
Difficulty Level<\/td>Moderate to Advanced<\/td><\/tr>
Useful For<\/td>School Exams & Olympiad Preparation<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n
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Concepts Used (Topics Covered)<\/h1>\n\n\n\n
    \n
  • Linear Polynomials<\/li>\n\n\n\n
  • Degree of Polynomial<\/li>\n\n\n\n
  • Polynomial Evaluation<\/li>\n\n\n\n
  • Linear Equations<\/li>\n\n\n\n
  • Linear Growth & Decay<\/li>\n\n\n\n
  • Graphs of Linear Equations<\/li>\n\n\n\n
  • Slope & y-intercept<\/li>\n\n\n\n
  • Coordinate Geometry<\/li>\n\n\n\n
  • Linear Relationships<\/li>\n\n\n\n
  • Pattern Formation<\/li>\n<\/ul>\n\n\n\n
    \n\n\n\n

    Important Formulas<\/h1>\n\n\n\n

    General Linear Equation<\/h2>\n\n\n\n
    \"image\"<\/figure>\n\n\n\n
    \n\n\n\n

    Quadratic Polynomial<\/h2>\n\n\n\n

    a<\/mi>x<\/mi>2<\/mn><\/msup>+<\/mo>b<\/mi>x<\/mi>+<\/mo>c<\/mi><\/mrow>ax^2+bx+c<\/annotation><\/semantics><\/math><\/p>\n\n\n\n
    \n\n\n\n

    Work Done Formula<\/h2>\n\n\n\n

    W=Fd<\/p>\n\n\n\n

    \n\n\n\n

    Temperature Conversion Formula<\/h2>\n\n\n\n
    \"image\"<\/figure>\n\n\n\n

    Questions & Step-by-Step Solutions<\/h1>\n\n\n\n

    Question 1<\/h1>\n\n\n\n

    Write a polynomial of degree 3 in variable x where coefficient of x<\/mi>2<\/mn><\/msup><\/mrow>x^2<\/annotation><\/semantics><\/math> is \u22127.<\/p>\n\n\n\n

    Solution<\/h2>\n\n\n\n

    One such polynomial is:x<\/mi>3<\/mn><\/msup>\u2212<\/mo>7<\/mn>x<\/mi>2<\/mn><\/msup>+<\/mo>5<\/mn>x<\/mi>+<\/mo>2<\/mn><\/mrow>x^3 – 7x^2 + 5x + 2<\/annotation><\/semantics><\/math><\/p>\n\n\n\n

    Final Answer<\/h3>\n\n\n\n

    \u2705 Polynomial:x<\/mi>3<\/mn><\/msup>\u2212<\/mo>7<\/mn>x<\/mi>2<\/mn><\/msup>+<\/mo>5<\/mn>x<\/mi>+<\/mo>2<\/mn><\/mrow>x^3 – 7x^2 + 5x + 2<\/annotation><\/semantics><\/math><\/p>\n\n\n\n
    \n\n\n\n

    Question 2<\/h1>\n\n\n\n

    Find the value of the following polynomials.<\/p>\n\n\n\n

    \n\n\n\n

    (i) 5<\/mn>x<\/mi>2<\/mn><\/msup>\u2212<\/mo>3<\/mn>x<\/mi>+<\/mo>7<\/mn><\/mrow>5x^2 – 3x + 7<\/annotation><\/semantics><\/math> when x<\/mi>=<\/mo>1<\/mn><\/mrow>x=1<\/annotation><\/semantics><\/math><\/h2>\n\n\n\n

    Solution<\/h3>\n\n\n\n

    5<\/mn>(<\/mo>1<\/mn>)<\/mo>2<\/mn><\/msup>\u2212<\/mo>3<\/mn>(<\/mo>1<\/mn>)<\/mo>+<\/mo>7<\/mn><\/mrow>5(1)^2 – 3(1) + 7<\/annotation><\/semantics><\/math>=<\/mo>5<\/mn>\u2212<\/mo>3<\/mn>+<\/mo>7<\/mn><\/mrow>= 5 – 3 + 7<\/annotation><\/semantics><\/math>=<\/mo>9<\/mn><\/mrow>= 9<\/annotation><\/semantics><\/math><\/p>\n\n\n\n

    Final Answer<\/h3>\n\n\n\n

    \u2705 Value = 9<\/strong><\/p>\n\n\n\n

    \n\n\n\n

    (ii) 4<\/mn>t<\/mi>3<\/mn><\/msup>\u2212<\/mo>t<\/mi>2<\/mn><\/msup>+<\/mo>6<\/mn><\/mrow>4t^3 – t^2 + 6<\/annotation><\/semantics><\/math> when t<\/mi>=<\/mo>a<\/mi><\/mrow>t=a<\/annotation><\/semantics><\/math><\/h2>\n\n\n\n

    Solution<\/h3>\n\n\n\n

    4<\/mn>a<\/mi>3<\/mn><\/msup>\u2212<\/mo>a<\/mi>2<\/mn><\/msup>+<\/mo>6<\/mn><\/mrow>4a^3 – a^2 + 6<\/annotation><\/semantics><\/math><\/p>\n\n\n\n

    Final Answer<\/h3>\n\n\n\n

    \u2705 Value = 4a3<\/sup>\u2212a2<\/sup>+6<\/strong><\/p>\n\n\n\n

    \n\n\n\n

    Question 3<\/h1>\n\n\n\n

    If a number is multiplied by 5<\/mn>2<\/mn><\/mfrac><\/mrow>\\frac{5}{2}<\/annotation><\/semantics><\/math>\u200b and 2<\/mn>3<\/mn><\/mfrac><\/mrow>\\frac{2}{3}<\/annotation><\/semantics><\/math>\u200b is added, the result becomes \u2212<\/mo>7<\/mn>12<\/mn><\/mfrac><\/mrow>-\\frac{7}{12}<\/annotation><\/semantics><\/math>\u200b. Find the number.<\/p>\n\n\n\n

    Solution<\/h2>\n\n\n\n

    Let number = x<\/mi><\/mrow>x<\/annotation><\/semantics><\/math>5<\/mn>2<\/mn><\/mfrac>x<\/mi>+<\/mo>2<\/mn>3<\/mn><\/mfrac>=<\/mo>\u2212<\/mo>7<\/mn>12<\/mn><\/mfrac><\/mrow>\\frac{5}{2}x + \\frac{2}{3} = -\\frac{7}{12}<\/annotation><\/semantics><\/math><\/p>\n\n\n\n

    Multiply by 12:30<\/mn>x<\/mi>+<\/mo>8<\/mn>=<\/mo>\u2212<\/mo>7<\/mn><\/mrow>30x + 8 = -7<\/annotation><\/semantics><\/math>30<\/mn>x<\/mi>=<\/mo>\u2212<\/mo>15<\/mn><\/mrow>30x = -15<\/annotation><\/semantics><\/math>x<\/mi>=<\/mo>\u2212<\/mo>1<\/mn>2<\/mn><\/mfrac><\/mrow>x = -\\frac{1}{2}<\/annotation><\/semantics><\/math>\u200b<\/p>\n\n\n\n

    Final Answer<\/h3>\n\n\n\n

    \u2705 Number = \u22121\/2<\/strong><\/p>\n\n\n\n

    \n\n\n\n

    Question 4<\/h1>\n\n\n\n

    A positive number is 5 times another number. If 21 is added to both numbers, one becomes twice the other. Find the numbers.<\/p>\n\n\n\n

    Solution<\/h2>\n\n\n\n

    Let smaller number = x<\/mi><\/mrow>x<\/annotation><\/semantics><\/math><\/p>\n\n\n\n

    Larger number = 5<\/mn>x<\/mi><\/mrow>5x<\/annotation><\/semantics><\/math><\/p>\n\n\n\n

    After adding 21:5<\/mn>x<\/mi>+<\/mo>21<\/mn>=<\/mo>2<\/mn>(<\/mo>x<\/mi>+<\/mo>21<\/mn>)<\/mo><\/mrow>5x+21 = 2(x+21)<\/annotation><\/semantics><\/math>5<\/mn>x<\/mi>+<\/mo>21<\/mn>=<\/mo>2<\/mn>x<\/mi>+<\/mo>42<\/mn><\/mrow>5x+21 = 2x+42<\/annotation><\/semantics><\/math>3<\/mn>x<\/mi>=<\/mo>21<\/mn><\/mrow>3x = 21<\/annotation><\/semantics><\/math>x<\/mi>=<\/mo>7<\/mn><\/mrow>x = 7<\/annotation><\/semantics><\/math><\/p>\n\n\n\n

    Larger number:5<\/mn>(<\/mo>7<\/mn>)<\/mo>=<\/mo>35<\/mn><\/mrow>5(7)=35<\/annotation><\/semantics><\/math><\/p>\n\n\n\n

    Final Answer<\/h3>\n\n\n\n

    \u2705 Numbers are 7 and 35<\/strong><\/p>\n\n\n\n

    \n\n\n\n

    Question 5<\/h1>\n\n\n\n

    You have \u20b9800 and save \u20b9250 every month. Find amount after:<\/p>\n\n\n\n

    \n\n\n\n

    (i) 6 months<\/h2>\n\n\n\n

    Solution<\/h3>\n\n\n\n

    800<\/mn>+<\/mo>250<\/mn>(<\/mo>6<\/mn>)<\/mo><\/mrow>800 + 250(6)<\/annotation><\/semantics><\/math>=<\/mo>800<\/mn>+<\/mo>1500<\/mn><\/mrow>= 800 + 1500<\/annotation><\/semantics><\/math>=<\/mo>2300<\/mn><\/mrow>= 2300<\/annotation><\/semantics><\/math><\/p>\n\n\n\n

    Final Answer<\/h3>\n\n\n\n

    \u2705 Amount after 6 months = \u20b92300<\/strong><\/p>\n\n\n\n

    \n\n\n\n

    (ii) 2 years<\/h2>\n\n\n\n

    2 years = 24 months800<\/mn>+<\/mo>250<\/mn>(<\/mo>24<\/mn>)<\/mo><\/mrow>800 + 250(24)<\/annotation><\/semantics><\/math>=<\/mo>800<\/mn>+<\/mo>6000<\/mn><\/mrow>= 800 + 6000<\/annotation><\/semantics><\/math>=<\/mo>6800<\/mn><\/mrow>= 6800<\/annotation><\/semantics><\/math><\/p>\n\n\n\n

    Final Answer<\/h3>\n\n\n\n

    \u2705 Amount after 2 years = \u20b96800<\/strong><\/p>\n\n\n\n

    \n\n\n\n

    Linear Pattern<\/h2>\n\n\n\n

    800<\/mn>+<\/mo>250<\/mn>n<\/mi><\/mrow>800 + 250n<\/annotation><\/semantics><\/math><\/p>\n\n\n\n
    \n\n\n\n

    Question 6<\/h1>\n\n\n\n

    The digits of a two-digit number differ by 3. If digits are interchanged and both numbers are added, sum becomes 143. Find numbers.<\/p>\n\n\n\n

    Solution<\/h2>\n\n\n\n

    Let tens digit = x<\/mi><\/mrow>x<\/annotation><\/semantics><\/math><\/p>\n\n\n\n

    Units digit = x<\/mi>+<\/mo>3<\/mn><\/mrow>x+3<\/annotation><\/semantics><\/math><\/p>\n\n\n\n

    Original number:10<\/mn>x<\/mi>+<\/mo>(<\/mo>x<\/mi>+<\/mo>3<\/mn>)<\/mo>=<\/mo>11<\/mn>x<\/mi>+<\/mo>3<\/mn><\/mrow>10x + (x+3)=11x+3<\/annotation><\/semantics><\/math><\/p>\n\n\n\n

    Interchanged number:10<\/mn>(<\/mo>x<\/mi>+<\/mo>3<\/mn>)<\/mo>+<\/mo>x<\/mi>=<\/mo>11<\/mn>x<\/mi>+<\/mo>30<\/mn><\/mrow>10(x+3)+x=11x+30<\/annotation><\/semantics><\/math><\/p>\n\n\n\n

    Their sum:11<\/mn>x<\/mi>+<\/mo>3<\/mn>+<\/mo>11<\/mn>x<\/mi>+<\/mo>30<\/mn>=<\/mo>143<\/mn><\/mrow>11x+3+11x+30=143<\/annotation><\/semantics><\/math>22<\/mn>x<\/mi>+<\/mo>33<\/mn>=<\/mo>143<\/mn><\/mrow>22x+33=143<\/annotation><\/semantics><\/math>22<\/mn>x<\/mi>=<\/mo>110<\/mn><\/mrow>22x=110<\/annotation><\/semantics><\/math>x<\/mi>=<\/mo>5<\/mn><\/mrow>x=5<\/annotation><\/semantics><\/math><\/p>\n\n\n\n

    Digits are 5 and 8.<\/p>\n\n\n\n

    Final Answer<\/h3>\n\n\n\n

    \u2705 Numbers are 58 and 85<\/strong><\/p>\n\n\n\n

    \n\n\n\n

    Question 7<\/h1>\n\n\n\n

    Find slope and y-intercept of given equations.<\/p>\n\n\n\n

    \n\n\n\n

    (i) y<\/mi>=<\/mo>\u2212<\/mo>3<\/mn>x<\/mi>+<\/mo>4<\/mn><\/mrow>y=-3x+4<\/annotation><\/semantics><\/math><\/h2>\n\n\n\n

    Slope = \u22123<\/p>\n\n\n\n

    y-intercept = 4<\/p>\n\n\n\n

    Cuts y-axis at:(<\/mo>0<\/mn>,<\/mo>4<\/mn>)<\/mo><\/mrow>(0,4)<\/annotation><\/semantics><\/math><\/p>\n\n\n\n
    \n\n\n\n

    (ii) 2<\/mn>y<\/mi>=<\/mo>4<\/mn>x<\/mi>+<\/mo>7<\/mn><\/mrow>2y=4x+7<\/annotation><\/semantics><\/math>2y=4x+7<\/h2>\n\n\n\n

    y<\/mi>=<\/mo>2<\/mn>x<\/mi>+<\/mo>7<\/mn>2<\/mn><\/mfrac><\/mrow>y=2x+\\frac{7}{2}<\/annotation><\/semantics><\/math><\/p>\n\n\n\n

    Slope = 2<\/p>\n\n\n\n

    y-intercept = 7<\/mn>\/<\/mi>2<\/mn><\/mrow>7\/2<\/annotation><\/semantics><\/math><\/p>\n\n\n\n
    \n\n\n\n

    (iii) 5<\/mn>y<\/mi>=<\/mo>6<\/mn>x<\/mi>\u2212<\/mo>10<\/mn><\/mrow>5y=6x-10<\/annotation><\/semantics><\/math><\/h2>\n\n\n\n

    y<\/mi>=<\/mo>6<\/mn>5<\/mn><\/mfrac>x<\/mi>\u2212<\/mo>2<\/mn><\/mrow>y=\\frac{6}{5}x-2<\/annotation><\/semantics><\/math><\/p>\n\n\n\n

    Slope = 6<\/mn>\/<\/mi>5<\/mn><\/mrow>6\/5<\/annotation><\/semantics><\/math><\/p>\n\n\n\n

    y-intercept = \u22122<\/p>\n\n\n\n

    \n\n\n\n

    (iv) 3<\/mn>y<\/mi>=<\/mo>6<\/mn>x<\/mi>\u2212<\/mo>11<\/mn><\/mrow>3y=6x-11<\/annotation><\/semantics><\/math><\/h2>\n\n\n\n

    y<\/mi>=<\/mo>2<\/mn>x<\/mi>\u2212<\/mo>11<\/mn>3<\/mn><\/mfrac><\/mrow>y=2x-\\frac{11}{3}<\/annotation><\/semantics><\/math><\/p>\n\n\n\n

    Slope = 2<\/p>\n\n\n\n

    y-intercept = \u2212<\/mo>11<\/mn>\/<\/mi>3<\/mn><\/mrow>-11\/3<\/annotation><\/semantics><\/math><\/p>\n\n\n\n
    \n\n\n\n

    Parallel Lines<\/h2>\n\n\n\n

    Equations (ii) and (iv) are parallel because slopes are same.<\/p>\n\n\n\n

    \n\n\n\n

    Question 8<\/h1>\n\n\n\n

    Temperature relation:<\/p>\n\n\n\n

    y<\/mi>=<\/mo>9<\/mn>5<\/mn><\/mfrac>(<\/mo>x<\/mi>\u2212<\/mo>273<\/mn>)<\/mo>+<\/mo>32<\/mn><\/mrow>y=\\frac{9}{5}(x-273)+32<\/annotation><\/semantics><\/math><\/p>\n\n\n\n
    \"image\"<\/figure>\n\n\n\n
    \n\n\n\n

    (i) Find Fahrenheit when x<\/mi>=<\/mo>313<\/mn>K<\/mi><\/mrow>x=313K<\/annotation><\/semantics><\/math><\/h2>\n\n\n\n

    Solution<\/h3>\n\n\n\n

    y<\/mi>=<\/mo>9<\/mn>5<\/mn><\/mfrac>(<\/mo>313<\/mn>\u2212<\/mo>273<\/mn>)<\/mo>+<\/mo>32<\/mn><\/mrow>y=\\frac{9}{5}(313-273)+32<\/annotation><\/semantics><\/math>=<\/mo>9<\/mn>5<\/mn><\/mfrac>(<\/mo>40<\/mn>)<\/mo>+<\/mo>32<\/mn><\/mrow>=\\frac{9}{5}(40)+32<\/annotation><\/semantics><\/math>=<\/mo>72<\/mn>+<\/mo>32<\/mn><\/mrow>=72+32<\/annotation><\/semantics><\/math>=<\/mo>104<\/mn><\/mrow>=104<\/annotation><\/semantics><\/math><\/p>\n\n\n\n

    Final Answer<\/h3>\n\n\n\n

    \u2705 Temperature = 104\u00b0F<\/strong><\/p>\n\n\n\n

    \n\n\n\n

    (ii) Find Kelvin when y<\/mi>=<\/mo>158<\/mn>\u00b0<\/mi>F<\/mi><\/mrow>y=158\u00b0F<\/annotation><\/semantics><\/math><\/h2>\n\n\n\n

    Solution<\/h3>\n\n\n\n

    158<\/mn>=<\/mo>9<\/mn>5<\/mn><\/mfrac>(<\/mo>x<\/mi>\u2212<\/mo>273<\/mn>)<\/mo>+<\/mo>32<\/mn><\/mrow>158=\\frac{9}{5}(x-273)+32<\/annotation><\/semantics><\/math><\/p>\n\n\n\n

    126<\/mn>=<\/mo>9<\/mn>5<\/mn><\/mfrac>(<\/mo>x<\/mi>\u2212<\/mo>273<\/mn>)<\/mo><\/mrow>126=\\frac{9}{5}(x-273)<\/annotation><\/semantics><\/math>70<\/mn>=<\/mo>x<\/mi>\u2212<\/mo>273<\/mn><\/mrow>70=x-273<\/annotation><\/semantics><\/math>x<\/mi>=<\/mo>343<\/mn><\/mrow>x=343<\/annotation><\/semantics><\/math><\/p>\n\n\n\n

    Final Answer<\/h3>\n\n\n\n

    \u2705 Temperature = 343 K<\/strong><\/p>\n\n\n\n

    \n\n\n\n

    Question 9<\/h1>\n\n\n\n

    Express work done relation when force = 3 units.<\/p>\n\n\n\n

    Solution<\/h2>\n\n\n\n

    Using:W<\/mi>=<\/mo>F<\/mi>d<\/mi><\/mrow>W=Fd<\/annotation><\/semantics><\/math><\/p>\n\n\n\n

    Force = 3W<\/mi>=<\/mo>3<\/mn>d<\/mi><\/mrow>W=3d<\/annotation><\/semantics><\/math><\/p>\n\n\n\n

    When distance = 2:W<\/mi>=<\/mo>3<\/mn>(<\/mo>2<\/mn>)<\/mo>=<\/mo>6<\/mn><\/mrow>W=3(2)=6<\/annotation><\/semantics><\/math><\/p>\n\n\n\n

    Final Answer<\/h3>\n\n\n\n

    \u2705 Equation:W<\/mi>=<\/mo>3<\/mn>d<\/mi><\/mrow>W=3d<\/annotation><\/semantics><\/math><\/p>\n\n\n\n

    \u2705 Work done = 6 units<\/strong><\/p>\n\n\n\n

    \n\n\n\n

    Question 10<\/h1>\n\n\n\n

    Graph passes through (1,5) and (3,11). Find polynomial.<\/p>\n\n\n\n

    Solution<\/h2>\n\n\n\n

    Slope:m<\/mi>=<\/mo>11<\/mn>\u2212<\/mo>5<\/mn><\/mrow>3<\/mn>\u2212<\/mo>1<\/mn><\/mrow><\/mfrac><\/mrow>m=\\frac{11-5}{3-1}<\/annotation><\/semantics><\/math>=<\/mo>6<\/mn>2<\/mn><\/mfrac>=<\/mo>3<\/mn><\/mrow>=\\frac{6}{2}=3<\/annotation><\/semantics><\/math><\/p>\n\n\n\n

    Equation:y<\/mi>=<\/mo>3<\/mn>x<\/mi>+<\/mo>b<\/mi><\/mrow>y=3x+b<\/annotation><\/semantics><\/math><\/p>\n\n\n\n

    Substitute point (1,5):5<\/mn>=<\/mo>3<\/mn>(<\/mo>1<\/mn>)<\/mo>+<\/mo>b<\/mi><\/mrow>5=3(1)+b<\/annotation><\/semantics><\/math>b<\/mi>=<\/mo>2<\/mn><\/mrow>b=2<\/annotation><\/semantics><\/math><\/p>\n\n\n\n

    Final Answer<\/h3>\n\n\n\n

    \u2705 Polynomial:p<\/mi>(<\/mo>x<\/mi>)<\/mo>=<\/mo>3<\/mn>x<\/mi>+<\/mo>2<\/mn><\/mrow>p(x)=3x+2<\/annotation><\/semantics><\/math><\/p>\n\n\n\n
    \n\n\n\n

    Common Mistakes<\/h1>\n\n\n\n

    \u274c Sign errors while solving equations
    \u274c Wrong substitution in polynomial evaluation
    \u274c Confusing slope with intercept
    \u274c Incorrect graph plotting<\/p>\n\n\n\n

    \n\n\n\n

    Exam Tips<\/h1>\n\n\n\n

    \u2714 Always simplify equations step-by-step
    \u2714 Remember slope formula carefully
    \u2714 Verify answers after solving
    \u2714 Practice graph questions regularly<\/p>\n\n\n\n

    \n\n\n\n

    Practice MCQs<\/h1>\n\n\n\n

    1. Degree of polynomial x<\/mi>3<\/mn><\/msup>+<\/mo>2<\/mn>x<\/mi>2<\/mn><\/msup>+<\/mo>1<\/mn><\/mrow>x^3+2x^2+1<\/annotation><\/semantics><\/math> is:<\/h2>\n\n\n\n

    A) 1
    B) 2
    C) 3
    D) 4<\/p>\n\n\n\n

    Answer<\/h3>\n\n\n\n

    \u2705 C) 3<\/p>\n\n\n\n

    \n\n\n\n

    2. Which equation represents a straight line?<\/h2>\n\n\n\n

    A) y<\/mi>=<\/mo>x<\/mi>2<\/mn><\/msup><\/mrow>y=x^2<\/annotation><\/semantics><\/math>
    B) y<\/mi>=<\/mo>2<\/mn>x<\/mi>+<\/mo>1<\/mn><\/mrow>y=2x+1<\/annotation><\/semantics><\/math>
    C) y<\/mi>=<\/mo>x<\/mi>3<\/mn><\/msup><\/mrow>y=x^3<\/annotation><\/semantics><\/math>
    D) y<\/mi>=<\/mo>2<\/mn>x<\/mi><\/msup><\/mrow>y=2^x<\/annotation><\/semantics><\/math><\/p>\n\n\n\n

    Answer<\/h3>\n\n\n\n

    \u2705 B) y<\/mi>=<\/mo>2<\/mn>x<\/mi>+<\/mo>1<\/mn><\/mrow>y=2x+1<\/annotation><\/semantics><\/math><\/p>\n\n\n\n
    \n\n\n\n

    3. In equation y<\/mi>=<\/mo>a<\/mi>x<\/mi>+<\/mo>b<\/mi><\/mrow>y=ax+b<\/annotation><\/semantics><\/math>, a<\/mi><\/mrow>a<\/annotation><\/semantics><\/math> represents:<\/h2>\n\n\n\n

    A) intercept
    B) constant
    C) slope
    D) variable<\/p>\n\n\n\n

    Answer<\/h3>\n\n\n\n

    \u2705 C) slope<\/p>\n\n\n\n

    \n\n\n\n

    4. Parallel lines have:<\/h2>\n\n\n\n

    A) Same intercept
    B) Same slope
    C) Same coordinates
    D) Same graph<\/p>\n\n\n\n

    Answer<\/h3>\n\n\n\n

    \u2705 B) Same slope<\/p>\n\n\n\n

    \n\n\n\n

    FAQ Section<\/h1>\n\n\n\n

    Q1. What is a linear polynomial?<\/h2>\n\n\n\n

    A polynomial having degree 1 is called a linear polynomial.<\/p>\n\n\n\n

    Q2. What is slope?<\/h2>\n\n\n\n

    Slope measures the steepness of a straight line.<\/p>\n\n\n\n

    Q3. What is y-intercept?<\/h2>\n\n\n\n

    It is the point where graph cuts the y-axis.<\/p>\n\n\n\n

    Q4. Why are linear relationships important?<\/h2>\n\n\n\n

    They help represent real-life situations mathematically.<\/p>\n\n\n\n

    Q5. How can graph questions be solved easily?<\/h2>\n\n\n\n

    By plotting accurate points and joining them carefully.<\/p>\n\n\n\n

    \n\n\n\n

    Practice more chapter-wise Maths solutions, MCQs, graph questions, and mock tests on MyMockMate<\/a><\/strong> and strengthen your Class 9 Mathematics preparation with smart learning resources!<\/p>\n\n\n\n

    <\/p>\n

    \"image_pdf\"Save as PDF<\/span><\/a>\"image_print\"Print<\/span><\/a> <\/span><\/div>\n
    \n\n\t\t\n
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      Short Intro The End-of-Chapter Exercises of Chapter 2 \u201cIntroduction to Linear Polynomials\u201d help students revise<\/p>\n","protected":false},"author":1,"featured_media":2168,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_surecart_dashboard_logo_width":"180px","_surecart_dashboard_show_logo":true,"_surecart_dashboard_navigation_orders":true,"_surecart_dashboard_navigation_invoices":true,"_surecart_dashboard_navigation_subscriptions":true,"_surecart_dashboard_navigation_downloads":true,"_surecart_dashboard_navigation_billing":true,"_surecart_dashboard_navigation_account":true,"postBodyCss":"","postBodyMargin":[],"postBodyPadding":[],"postBodyBackground":{"backgroundType":"classic","gradient":""},"footnotes":"","jetpack_publicize_message":"","jetpack_publicize_feature_enabled":true,"jetpack_social_post_already_shared":true,"jetpack_social_options":{"image_generator_settings":{"template":"highway","default_image_id":0,"font":"","enabled":false},"version":2}},"categories":[22,4,11],"tags":[737,226,740,736,727,163,741,739,738,677,715,742,688,687,82,722,673],"class_list":["post-2164","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-cbse","category-class-9","category-maths-class-9","tag-algebra-solutions-class-9","tag-chapter-2-maths-solutions","tag-class-9-algebra-chapter","tag-class-9-maths-solutions","tag-coordinate-geometry-basics","tag-end-of-chapter-exercise-solutions","tag-ganita-manjari-solutions","tag-graph-questions-maths","tag-linear-equations-solutions","tag-linear-polynomials-solutions","tag-linear-relationships","tag-maths-exercise-solutions","tag-mymockmate-maths","tag-polynomial-evaluation","tag-polynomial-graphs","tag-slope-and-intercept","tag-step-by-step-maths-solutions"],"jetpack_publicize_connections":[],"_links":{"self":[{"href":"https:\/\/mymockmate.com\/notes\/wp-json\/wp\/v2\/posts\/2164","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/mymockmate.com\/notes\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/mymockmate.com\/notes\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/mymockmate.com\/notes\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/mymockmate.com\/notes\/wp-json\/wp\/v2\/comments?post=2164"}],"version-history":[{"count":1,"href":"https:\/\/mymockmate.com\/notes\/wp-json\/wp\/v2\/posts\/2164\/revisions"}],"predecessor-version":[{"id":2169,"href":"https:\/\/mymockmate.com\/notes\/wp-json\/wp\/v2\/posts\/2164\/revisions\/2169"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/mymockmate.com\/notes\/wp-json\/wp\/v2\/media\/2168"}],"wp:attachment":[{"href":"https:\/\/mymockmate.com\/notes\/wp-json\/wp\/v2\/media?parent=2164"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/mymockmate.com\/notes\/wp-json\/wp\/v2\/categories?post=2164"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/mymockmate.com\/notes\/wp-json\/wp\/v2\/tags?post=2164"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}