{"id":4778,"date":"2026-06-18T12:58:09","date_gmt":"2026-06-18T07:28:09","guid":{"rendered":"https:\/\/mymockmate.com\/notes\/?p=4778"},"modified":"2026-06-18T15:43:37","modified_gmt":"2026-06-18T10:13:37","slug":"ncert-class-10-maths-chapter-1-exercise-1-1-solutions-real-numbers","status":"publish","type":"post","link":"https:\/\/mymockmate.com\/notes\/ncert-class-10-maths-chapter-1-exercise-1-1-solutions-real-numbers\/","title":{"rendered":"NCERT Class 10 Maths Chapter 1 Exercise 1.1 Solutions | Real Numbers"},"content":{"rendered":"
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Short Introduction<\/h2>\n\n\n\n

NCERT Class 10 Maths Chapter 1 (Real Numbers) Exercise 1.1 focuses on the Fundamental Theorem of Arithmetic, Prime Factorisation Method, HCF (Highest Common Factor) and LCM (Least Common Multiple). These concepts form the foundation for many higher mathematical topics. In this article, we provide detailed step-by-step solutions to all questions of Exercise 1.1 in an exam-oriented manner.<\/p>\n\n\n\n

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Quick Information Box<\/h1>\n\n\n\n
Particular<\/th>Details<\/th><\/tr><\/thead>
Class<\/td>10<\/td><\/tr>
Subject<\/td>Mathematics<\/td><\/tr>
Chapter<\/td>Real Numbers<\/td><\/tr>
Exercise<\/td>1.1<\/td><\/tr>
Board<\/td>CBSE \/ NCERT<\/td><\/tr>
Main Topics<\/td>Prime Factorisation, HCF, LCM<\/td><\/tr>
Difficulty Level<\/td>Easy to Moderate<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n
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Concepts Used (Topics Covered)<\/h1>\n\n\n\n

✓ Prime Numbers<\/p>\n\n\n\n

✓ Composite Numbers<\/p>\n\n\n\n

✓ Prime Factorisation<\/p>\n\n\n\n

✓ Fundamental Theorem of Arithmetic<\/p>\n\n\n\n

✓ Highest Common Factor (HCF)<\/p>\n\n\n\n

Related Topic to Read more<\/span>NCERT Class 10 Maths Real Number Exercise 1.2 Solutions | MyMockMate<\/span><\/a><\/div>

✓ Least Common Multiple (LCM)<\/p>\n\n\n\n

✓ Verification of HCF × LCM = Product of Numbers<\/p>\n\n\n\n

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Important Formulas<\/h1>\n\n\n\n

1. Fundamental Theorem of Arithmetic<\/h3>\n\n\n\n

Every composite number can be expressed as a product of prime factors in a unique way.<\/p>\n\n\n\n

2. HCF Formula<\/h3>\n\n\n\n

HCF = Product of the smallest powers of common prime factors.<\/p>\n\n\n\n

3. LCM Formula<\/h3>\n\n\n\n

LCM = Product of the greatest powers of all prime factors involved.<\/p>\n\n\n\n

4. Relationship<\/h3>\n\n\n\n

LCM × HCF = Product of the given two numbers<\/p>\n\n\n\n

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Question 1<\/h1>\n\n\n\n

Express each number as a product of its prime factors.<\/h2>\n\n\n\n

(i) 140<\/h3>\n\n\n\n

Solution<\/h4>\n\n\n\n
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(ii) 156<\/h3>\n\n\n\n

Solution<\/h4>\n\n\n\n
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(iii) 3825<\/h3>\n\n\n\n

Solution<\/h4>\n\n\n\n
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(iv) 5005<\/h3>\n\n\n\n

Solution<\/h4>\n\n\n\n
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(v) 7429<\/h3>\n\n\n\n

Solution<\/h4>\n\n\n\n
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Question 2<\/h1>\n\n\n\n

Find the LCM and HCF of the following pairs of integers and verify that:<\/h2>\n\n\n\n

LCM × HCF = Product of the two numbers<\/h3>\n\n\n\n
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(i) 26 and 91<\/h3>\n\n\n\n
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(ii) 510 and 92<\/h2>\n\n\n\n
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(iii) 336 and 54<\/h2>\n\n\n\n

<\/h3>\n\n\n\n
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Question 3<\/h2>\n\n\n\n

Find the LCM and HCF of the following integers by applying the prime factorisation method.<\/h2>\n\n\n\n

(i) 12, 15 and 21<\/h3>\n\n\n\n
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(ii) 17, 23 and 29<\/h3>\n\n\n\n
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(iii) 8, 9 and 25<\/h3>\n\n\n\n
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Question 4<\/h1>\n\n\n\n

Given that HCF (306, 657) = 9, find LCM (306, 657).<\/h2>\n\n\n\n
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Question 5<\/h1>\n\n\n\n

Check whether 6ⁿ can end with the digit 0 for any natural number n.<\/h2>\n\n\n\n
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Question 6<\/h1>\n\n\n\n

Explain why the following numbers are composite.<\/h2>\n\n\n\n

(i) 7 × 11 × 13 + 13<\/h3>\n\n\n\n
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(ii) 7 × 6 × 5 × 4 × 3 × 2 × 1 + 5<\/h3>\n\n\n\n
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Question 7<\/h1>\n\n\n\n

There is a circular path around a sports field. Sonia takes 18 minutes to drive one round of the field, while Ravi takes 12 minutes for the same. Suppose they both start at the same point and at the same time, and go in the same direction. After how many minutes will they meet again at the starting point?<\/h2>\n\n\n\n
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Common Mistakes<\/h1>\n\n\n\n
Related Topic to Read more<\/span>NCERT Class 10 Maths Exercise 2.1 Solutions | Polynomials<\/span><\/a><\/div>

❌ Taking highest powers while finding HCF.<\/p>\n\n\n\n

❌ Taking smallest powers while finding LCM.<\/p>\n\n\n\n

❌ Forgetting to verify HCF × LCM relation.<\/p>

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❌ Missing a prime factor during factorisation.<\/p>\n\n\n\n

❌ Arithmetic calculation mistakes.<\/p>\n\n\n\n

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Exam Tips<\/h1>\n\n\n\n

✅ Always write prime factorisation neatly.<\/p>\n\n\n\n

Related Topic to Read more<\/span>Class 10 Maths Exercise 2.2 Solutions | Relationship Between Zeroes and Coefficients<\/span><\/a><\/div>

✅ Use exponent form wherever possible.<\/p>\n\n\n\n

✅ Verify answers in LCM-HCF questions.<\/p>\n\n\n\n

✅ Show all calculation steps.<\/p>\n\n\n\n

✅ Learn prime numbers up to 100.<\/p>\n\n\n\n

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Practice MCQs<\/h1>\n\n\n\n

1. Prime factorisation of 180 is:<\/h3>\n\n\n\n

A) 2² × 3² × 5 ✓<\/p>\n\n\n\n

B) 2³ × 3² × 5<\/p>\n\n\n\n

C) 2² × 3 × 5²<\/p>\n\n\n\n

D) 2 × 3² × 5²<\/p>\n\n\n\n

2. HCF of 24 and 36 is:<\/h3>\n\n\n\n

A) 6<\/p>\n\n\n\n

B) 12 ✓<\/p>\n\n\n\n

C) 18<\/p>\n\n\n\n

D) 24<\/p>\n\n\n\n

3. LCM of 12 and 18 is:<\/h3>\n\n\n\n

A) 24<\/p>\n\n\n\n

B) 30<\/p>\n\n\n\n

C) 36 ✓<\/p>\n\n\n\n

D) 48<\/p>\n\n\n\n

4. A number ending with 0 must contain factor:<\/h3>\n\n\n\n

A) 3<\/p>\n\n\n\n

B) 7<\/p>\n\n\n\n

C) 11<\/p>\n\n\n\n

D) 5 ✓<\/p>\n\n\n\n

5. HCF × LCM equals:<\/h3>\n\n\n\n

A) Sum of numbers<\/p>\n\n\n\n

B) Difference<\/p>\n\n\n\n

C) Product of numbers ✓<\/p>\n\n\n\n

D) Quotient<\/p>\n\n\n\n

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FAQ Section<\/h1>\n\n\n\n

Q1. What is the Fundamental Theorem of Arithmetic?<\/h3>\n\n\n\n

Every composite number can be expressed uniquely as a product of prime factors.<\/p>\n\n\n\n

Q2. What is HCF?<\/h3>\n\n\n\n

The Highest Common Factor is the greatest number that divides all given numbers exactly.<\/p>\n\n\n\n

Q3. What is LCM?<\/h3>\n\n\n\n

The Least Common Multiple is the smallest common multiple of given numbers.<\/p>\n\n\n\n

Q4. Which method is used in Exercise 1.1?<\/h3>\n\n\n\n

Prime Factorisation Method.<\/p>\n\n\n\n

Q5. Is Exercise 1.1 important for boards?<\/h3>\n\n\n\n

Yes, HCF, LCM and Prime Factorisation are frequently asked in CBSE examinations.<\/p>\n\n\n\n

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