Tag: Exercise 5.2 Solutions

Differentiation Using the Chain Rule | NCERT Class 12 Mathematics Quick Facts dydx=dydu⋅dudx\frac{dy}{dx}=\frac{dy}{du}\cdot\frac{du}{dx} ddx(sin⁡x)=cos⁡x\frac{d}{dx}(\sin x)=\cos xddx(cos⁡x)=−sin⁡x\frac{d}{dx}(\cos x)=-\sin xddx(tan⁡x)=sec⁡2x\frac{d}{dx}(\tan x)=\sec^2xddx(cot⁡x)=−csc⁡2x\frac{d}{dx}(\cot x)=-\csc^2xddx(sec⁡x)=sec⁡xtan⁡x\frac{d}{dx}(\sec x)=\sec x\tan xddx(xn)=nxn−1\frac{d}{dx}(x^n)=nx^{n-1} Story Imagine…